Source code for bokeh.util.warnings
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# Copyright (c) 2012 - 2023, Anaconda, Inc., and Bokeh Contributors.
# All rights reserved.
#
# The full license is in the file LICENSE.txt, distributed with this software.
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''' Provide Bokeh-specific warning subclasses.
The primary use of these subclasses to to force them to be unconditionally
displayed to users by default.
'''
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# Boilerplate
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from __future__ import annotations
import logging # isort:skip
log = logging.getLogger(__name__)
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# Imports
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# Standard library imports
import inspect
import os
import warnings # lgtm [py/import-and-import-from]
from typing import Type
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# Globals and constants
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__all__ = (
'BokehDeprecationWarning',
'BokehUserWarning',
'find_stack_level',
'warn',
)
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# General API
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[docs]class BokehDeprecationWarning(DeprecationWarning):
''' A Bokeh-specific ``DeprecationWarning`` subclass.
Used to selectively filter Bokeh deprecations for unconditional display.
'''
[docs]class BokehUserWarning(UserWarning):
''' A Bokeh-specific ``UserWarning`` subclass.
Used to selectively filter Bokeh warnings for unconditional display.
'''
def warn(message: str, category: Type[Warning] | None = None, stacklevel: int | None = None) -> None:
if stacklevel is None:
stacklevel = find_stack_level()
warnings.warn(message, category, stacklevel=stacklevel)
[docs]def find_stack_level() -> int:
"""Find the first place in the stack that is not inside Bokeh.
Inspired by: pandas.util._exceptions.find_stack_level
"""
import bokeh
pkg_dir = os.path.dirname(bokeh.__file__)
# https://stackoverflow.com/questions/17407119/python-inspect-stack-is-slow
frame = inspect.currentframe()
n = 0
while frame:
fname = inspect.getfile(frame)
if fname.startswith(pkg_dir):
frame = frame.f_back
n += 1
else:
break
return n
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# Dev API
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# Private API
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# Code
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